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Richter Scale |
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Casualties | ||
Tsunamis | ||
Quake-Proofing | ||
Earthquake Preparation | ||
Earthquake Insurance |
Seismic Waves (to top menu)
1) | d=vt t = 600km / 6km/s t= 100 sec( it takes 100 sec for the P wave to reach Vancouver) d= vt t= 600km/4km/s t= 150 sec ( it takes 150 sec for S wave to reach Vancouver) Therefore the P wave reaches Vancouver 50 sec faster than S wave. |
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2) | With an increase in distance, the range of P and S wave increases over time. | ||||||
3) | Closest: Vernon(44 sec), Nelson(56 sec), Cranbrook (70 sec) | ||||||
4) | 390 km for an SP interval of 40 sec | ||||||
5) | slope:
rise/run (61sec - 35sec ) / (600km- 340km) slope: 1/10 |
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6) | You would need a minimum of two circles because the tangent of two circles will represent an epicenter. | ||||||
7) | Looking at the map with the three circles, any point lying on the green circle is a potential epicentre. | ||||||
8) | The
three circles should intersect near Port Alberni.
(x-4.5)2 +
(y+4.5)2 = 46.93 ( Cranbook ) |
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C H A L L E N G E |
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Richter Scale (to top menu)
1) | 100 times (10 X 10). |
2) | 1000 times (10 X 10 X 10). |
3) | 5.01 times. |
4) | 6.31 X 105 times. |
5) | 1.12 X 1013 kWh. |
6) | 3.16 X 1013 kWh. |
7) | 3.61 X 1013 years. |
Casualties (to top menu)
1) | Mean = 16140, Median = 4000, Mode = 4000. |
2) | Maximum = 8.2, Mean = 7.35. |
3) | In general, the greater the magnitude of the earthquake, the larger the number of casualties. |
4) | Answers may vary. Plot may appear highly exponential (beginning low and increasing quickly). |
5) | Answers will vary greatly depending on accuracy of the scatter plot, and function used for approximation. |
Tsunamis (to top menu)
1) | Plugging 4500 m into the wave-speed equation, the
answer is equal to: c = sqrt (9.8 x 4500) = 210 m/s Converting this into km/h: 210 m/s x (1 km/1000 m) x (3600 s/h) = 756 km/h |
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2) |
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Quake-Proofing (to top menu)
1) |
Assuming we install one beam in each rectangle, on the sides of the building, we will need 12 beams in total: 6 longer beams and 6 shorter beams. The length of a beam may be found by using the Pythagorean Triangle property: a2 + b2 = c2 Therefore, the length of a longer beam is equal to: sqrt(152 + 102) = sqrt(325) = 18.03 m Likewise, the length of a shorter beam is equal to: sqrt(102 + 102) = sqrt(200) = 14.14 m The total beam length is equal to : (6 x 18.03) + (6 x 14.14) = 193.03 m The cost, therefore, is equal to: $1000/m x 193.03 m = $193,030 |
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2) |
Half of the total beam length from the previous is equal to: 193.03/2 = 96.52 m The cost, therefore, is equal to: $1900/m x 96.52 m = $183,378 The amount of money saved is equal to: $193,030 - 183,378 = $9,652 |
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3) | Draw a simple triangle relating the initial and
final positions of the person.
The horizontal distance,
x, may be calculated as: |
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4) | Assuming the Transamerica building swayed approximately 1ft from side to side, it is safe to say that a horizontal displacement of 2.61 m is greater than 1 ft. The answer, therefore, is YES. |
Earthquake Preparation (to top menu)
1) | (72 hours)(60min/hour)(60min/sec) = 259200 seconds. |
2) | (4mL)/(4500mL) = .08889%. |
3) | d =
4.9 t2 => 3m =
4.9 t2 => t =
.7824s. v = 9.8t => v = 9.8(.7824s) => 7.6681m/s. |
Earthquake Insurance (to top menu)
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